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Boolean expression error in variable.
Posted Apr 2, 2012, 1:24 a.m. EDT 1 Reply
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dear all,
i have a boolean logic expression,
if t >= 0, t < 0.2
F = 1./(1+exp(-140*(t-0.08)))
if t >= 0.2 and t< 1
F = 1./(1+exp(60.61*(t-0.35)))
when i use below boolean expression in the variable, it end up that the the two statement is added up and the maximum y magnitude jump to 2, while when i use matlab, it is 1.
(t>=0)*(1/(1+exp(-140*(t[s]-0.08))))+(t>0 && t<0.2)*(1/(1+exp(-140*(t[s]-0.08))))+(t>=0.2&&t<1)*(1/(1+exp(60.61*(t[s]-0.35))))
can someone give me some me some help or hint where i make the mistake?
Thank you.
i have a boolean logic expression,
if t >= 0, t < 0.2
F = 1./(1+exp(-140*(t-0.08)))
if t >= 0.2 and t< 1
F = 1./(1+exp(60.61*(t-0.35)))
when i use below boolean expression in the variable, it end up that the the two statement is added up and the maximum y magnitude jump to 2, while when i use matlab, it is 1.
(t>=0)*(1/(1+exp(-140*(t[s]-0.08))))+(t>0 && t<0.2)*(1/(1+exp(-140*(t[s]-0.08))))+(t>=0.2&&t<1)*(1/(1+exp(60.61*(t[s]-0.35))))
can someone give me some me some help or hint where i make the mistake?
Thank you.
1 Reply Last Post Apr 2, 2012, 12:51 p.m. EDT
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Posted:
1 decade ago
(t>=0)*(1/(1+exp(-140*(t[s]-0.08))))+(t>0 && t<0.2)*(1/(1+exp(-140*(t[s]-0.08))))+(t>=0.2&&t<1)*(1/(1+exp(60.61*(t[s]-0.35))))
shouldn't the first term be for t<=0?